Question

a wire is looped in the form of a circle of diameter 70 cm if it is rebent in the form of a square what will be the length of each side of a the square
​

Answer 1

diameter of circle = 70cm

radius = 70/2 = 35cm

perimeter of the wire(circle) = perimeter of wire(square)

=> 2πr = 4a

=> 2×22/7×35 = 4a

=> 2×22×5 = 4a

=> 220 = 4a

=> a = 220/4

=> a = 55

hence, the length of the each side of the square is 55cm

I hope this answer helps you.

Answer 2

Question:-

a wire is looped in the form of a circle of diameter 70 cm if it is rebent in the form of a square what will be the length of each side of a the square

Answer:-

Given:-

$Diameter \: Of \: a \: circle \: formed \: by \: looped \: wire \: \longrightarrow\: 70cm. \\ \\ \longrightarrow \frac{70}{2} \\ \\ \longrightarrow \: 35cm$

We Get The Radius ...

Now,

$perimeter \: of \: the \: circle \: wire = perimeter \: of \: the \: Square \: wire$

$\longrightarrow2 \: \pi \: r = 4 \times side \\ \\ \longrightarrow2 \times \frac{22}{7} \times 35 = 4 \times side \\ \\ \longrightarrow \frac{44}{7} \times 35 = 4 \times side \\ \\ \longrightarrow220 = 4 \times side \\ \\ \longrightarrow \frac{220}{4} = side \\ \\ \longrightarrow55cm$

$so \: the \: length \: of \: each \: side \: of \: the \: square \: is \: 55cm.$