A wire is replaced by another wire of same length and material but of double the diameter. What will be the effect on the increase in its length under a given load?
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1
Answer:
Suppose Resistance of A as Ra and resistance of B as Rb.
Ra=Rb
PaLa/Aa = PbLb/Ab
Pa= Rho for conductor a; Pb= Rho for Conductor B
Aa= Area of A; Ab= Area of B
La= Length of A; Lb= length of B.
Where length of both are same, La=Lb
Pa/Aa = Pb/Ab
or
Pa/Pb = Aa/Ab
Condition that Pa>Pb means Pa/Pb is greater than 1.
Pa/Pb=Aa/Ab >1
Aa/Ab >1
Or
Aa > Ab
The A conductor is thicker than B.
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