Question

a wire is stretched so that its length becomes 6/5 times its original length. If its original resistance is 25 Ω, find its new resistance and resistivity

Answer 1

resistivity doesnt change with length it is constant for a material

but resistance is proportional to length

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Answer 2

R = p L/A

R = 25 ohm

Volume of material in the conductor = LA

Vol of the conductor remains the same

Vol = AL

= A'L'

A' = AL/L'

After streching the wire

L' = 6L/5

A' = 5AL/6L

= 5A/6

Resistance of streched wire = R'

= pL'/A'

= p(6L/5) × {6 / (5A) }

R' = 36pL / 25A

R' = 36R / 25

Now Resistance ,

= 36×25 / 25ohm

= 36 Ohm