A wire is stretched so that its length becomes 6/5 times its original length. If its original resistance is 25 ohm find its new RESISTIVITY.
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Answer:Since, the length of the wire becomes 6/5 times its original length; hence there will definitely be some change in cross sectional area. Now we know that, volume = Mass/Density and since neither mass nor density has changed due to change in length, thus volume must remain constant. Thus, R2 = 1.44 *25 = 36 Ohm.
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Answer:
Answer:Since, the length of the wire becomes 6/5 times its original length; hence there will definitely be some change in cross sectional area. Now we know that, volume = Mass/Density and since neither mass nor density has changed due to change in length, thus volume must remain constant. Thus, R2 = 1.44 *25 = 36 Ohm.
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