Physics, asked by Anonymous, 10 months ago

A wire is stretched so that its length becomes 6/5 times its original length. If its original resistance is 25 ohm find its new RESISTIVITY.

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Answered by rayyanmdk

1

Answer:Since, the length of the wire becomes 6/5 times its original length; hence there will definitely be some change in cross sectional area. Now we know that, volume = Mass/Density and since neither mass nor density has changed due to change in length, thus volume must remain constant. Thus, R2 = 1.44 *25 = 36 Ohm.

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Answered by Anonymous

6

Answer:

Answer:Since, the length of the wire becomes 6/5 times its original length; hence there will definitely be some change in cross sectional area. Now we know that, volume = Mass/Density and since neither mass nor density has changed due to change in length, thus volume must remain constant. Thus, R2 = 1.44 *25 = 36 Ohm.

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