Question

a wire is stretched so that its length becomes 6/5 times its original length full stop if it original resistance is 25 ohm, find its new resistance and resistivity

Answer 1

R = rho×L/A
25= rho×L/A
R' = rho× 6/5L÷A
R'= 6/5 [rho × L/A]
R' = 6/5[R]
R'= 6/5 (25)
R'= 30
resistivity of a conductor does not change as it is a constant.

Answer 2

R = p L/A

R = 25 ohm

Volume of material in the conductor = LA

Vol of the conductor remains the same

Vol = AL

= A'L'

A' = AL/L'

After streching the wire

L' = 6L/5

A' = 5AL/6L

= 5A/6

Resistance of streched wire = R'

= pL'/A'

= p(6L/5) × {6 / (5A) }

R' = 36pL / 25A

R' = 36R / 25

Now Resistance ,

= 36×25 / 25ohm

= 36 Ohm