Physics, asked by panwardeepanshi11, 3 months ago

A wire is stretched so that its length becomes 6/5 times of its original length. If its original resistance is 25 Ω find its new resistance. Give justification for your answer in each case.​

Answers

Answered by swatiChauhan786gmail
0

Answer:

A wire is stretched so that its length becomes 6/5 times its original length. If its original resistance is 25 ohm find its new resistance and resistivity

Explanation:

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Answered by muhammedsinanpk12
0

Answer:

here we can see the resistance is 25 ohm .

resistance = 25 ohm

length after stretched = 6/5

length increased = 1/5

here ,

area of cross section is decreased .

1/5 area of cross section decreased .

that means ,

area of cross section = 4/5

we are going to equations :

resistivity = resistance × area of cross section / length

resistance : R

resistivity : p(it is not p , it is rho , icant type it , please use rho )

area of cross section = A

length = l

then we are going to calculate it :

p = R × A / l

in other words we can change this equation :

R = p × l/A

here , R = 25 ohm

25 = p × l / A

this time ( length was increased and area of cross section was decreased )

R = p × (6/5× l) /(4/5A)

then starting calculation :

level of increased = (p × (6/5× l) /(4/5A))/p × l / A

here same values are cancelled .......

we get :

(6/5)/(4/5) = 1.2/0.8

= 12 / 8 = 2.5

here we get it .......

R = 25 × 2.5 = 37.5

RESISTANCE = 37.5 ohm

NOTE : PLEASE USE OMEGA SIGN EXCEPT OHM

I DON'T KNOW HOW FAR IS IT IS CORRECT . CHECK YOUR SELF . GOOD LUCK .......

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