A wire is stretched so that its length becomes 6/5 times of its original length.if its oruginal resistance is 25 ohm, find its new resistance.
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R=rho×L/A.....1
R is directly proportional to L
Now L has become 6/5 of L is 6/5×L
Let new R be R`
Substitute the new value of length in the formula and we will get
....R`=rho 6/5L /A
Or R`=6/5 rho L/A......2
Comparing 1 and 2 we get
R`=6/5 R
So the new resistance will be
R`=6/5×25=30ohm
R is directly proportional to L
Now L has become 6/5 of L is 6/5×L
Let new R be R`
Substitute the new value of length in the formula and we will get
....R`=rho 6/5L /A
Or R`=6/5 rho L/A......2
Comparing 1 and 2 we get
R`=6/5 R
So the new resistance will be
R`=6/5×25=30ohm
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