A wire is stretched to increase its length by 5%.Calculate the percentage change in resistance
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It is given l'=l + 5% of l =l +5/100 l = l(1+5/100)
Therefore A'=A/(1+5/100)
R'=pl'/A' =[pl×(1+5/100)]/[A/(1+5/100)]
=[pl×(1+5/100)^2] /A
=R×(1+10/100)
Percentage increase in resistance =R'-R/R×100 =10%
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