Question

A wire is stretched to reduce its diameter to half of its previous value what would be its new resistance

Answer 1

Answer:

the new resistance become 4 times its original resistance, when diameter of given wire is halved. a copper wire of resistivity r is streched to reduce its diameter to half of its previous value.

Answer 2

Answer:

R inversely proportional to Area

area of wire = πr^2 d will reduce thus r will be half

1/2^2= 1/4 thus resistance will increase by 4

Hope it helps you...