A wire is the shape of square of side 10cm.If the same wire is bent into a rectangle of length 12 cm.find its breadth.Also find the difference in their areas
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Ritanya:
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hey...
perimeter of square (length of wire) = 4s
= 4 x 10
= 40cm
perimeter of rectangle = 2(l+b)
40 = 2(l+b)
40/2 = 12 + b
20 - 12 = b
b = 8cm
Area of square = S x S
= 10 x 10
= 100cm^2
Area of rectangle = l x b
= 12 x 8
= 96 cm^2
Therefore, Area of square is greater than Area of rectangle by 4cm^2
perimeter of square (length of wire) = 4s
= 4 x 10
= 40cm
perimeter of rectangle = 2(l+b)
40 = 2(l+b)
40/2 = 12 + b
20 - 12 = b
b = 8cm
Area of square = S x S
= 10 x 10
= 100cm^2
Area of rectangle = l x b
= 12 x 8
= 96 cm^2
Therefore, Area of square is greater than Area of rectangle by 4cm^2
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