Question

a wire length 96m, is bent to form a right angled triangle with hypotenuse 40m; find the area of the triangle​

Answer 1

Answer:

384 m²

Step-by-step explanation: Let the height and base of the triangle be 'x' and 'y' respectively. So, x² + y² = 40²    [Pythagoras theorem]

  Perimeter of Δ = length of wire

⇒ height + base + hypotenuse = 96

⇒ x + y + 40 = 96

⇒ x + y = 56

           Square on both sides,

⇒ (x + y)² = 56²

⇒ x² + y² + 2xy = 3136

⇒ 40² + 2xy = 3136

⇒ 2xy = 1536

⇒ (2xy)/4 = (1536)/4    [Divide sides by 4]

⇒ (1/2) xy = 384

       Notice that area of triangle = 1/2 * height * base

Hence,

Area of triangle = 1/2 xy

                          = 384    [from above]

Answer 2

refer attachment ( ur answer is in it)