A wire loaded by a weight of density 7.6 g /cm³is
found to measure 90 cm. On immersing the weight
in water, the length decreased by 0.18 cm. Find the
original length of wire.
Answers
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Answer:
88.632 cm
Explanation:
ρ=7.6g/cm³
l+Δl=90cm
Δl=wl/AY….(1)
Δl−0.18=(w−(w/ρ0) ρl)l/AY…..(2)
(Δl−0.18)/ Δl=1−ρl/ρo
1−0.18/Δl=1−1/7.6
Δl=7.6×0.18
l+Δl=90
l=90−7.6×0.18=88.632cm