Question

A wire made of silver i. the form of nose ring of radius 42 mm .it is bent into a square .. determine the side of square

Answer 1

perimeter of the nose ring is
$2\pi \times 42 = 264mm$
perimeter of the square is 4a where a is the side. that is
$4a = 264 \\ ie. \: a = 66mm$

Answer 2

Radius , r = 42 cm
length of the wire = circumference = 2πr = 2*(22/7)*42 = 264 cm
When the same wire is bent in the form of square then length of wire remains same.
Let 's' be the side of square.
perimeter of square = 264
 so, 4s = 264
    we get, s = 264/4 = 66 cm
side of the square, s = 66 cm