Question

A wire of 10 m long, 0.2 mm in diameter and has a resistance of 10 ohm. Calculate the resistivity of this material.​

Answer 1

Answer:

Ra/l=ρ

=10(πr²)/10

=πr²=3.14*2*10⁻⁴=6.28*10⁸Ωm

Explanation:hope it helps/////

Answer 2

Answer is 3.14× 10^-6

Explanation-

Given,

Length, l= 10 m

Resistance,R = 10 ohm

Diameter= 0.2 mm

Radius, r = 0.1 mm = 1×10^-3 m (1mm= 1×10^-3m)

Cross sectional area,A=3.14×1×1×10^-3×10^-3

Using formula,

P= (R×A)/l

P=( 10× 3.14×1×1×10^-3×10^-3)/10

On solving we will get,

P= 3.14 ×10^-6 ohm-m

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