A wire of 12ohm resistance is stretched to double it's length.find out the new resistance of the wire..
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r= pl/a
12=pl/a{1}
since,
r1=p(2l)/(a/2)
r1=p(4l/a)
put {1}eq in it
r1=12×4
r1=48 omega
12=pl/a{1}
since,
r1=p(2l)/(a/2)
r1=p(4l/a)
put {1}eq in it
r1=12×4
r1=48 omega
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