Question

a wire of 15 ohm resistance is gradually stretched to double its original length. it is then cut into two equal parts. these parts are connected in parallel across a 3 V cell. find the current drawn from the cell

Answer 1

1 ohm 2 ohms etc. I think

Answer 2

Answer:

Explanation:When length of a given wire is made n-times by strecting it, its resistance becomes n2 times i.e., R' =n2R = (2)2 x 15 = 60Ω  Resistance of each half part 60/2 = 30Ω When both parts are connected in parallel, final resistance = 30/2 = 15Ω Current drawn from battery, I = V/R = 3.0/15 = 0.2ARead more on Sarthaks.com - https://www.sarthaks.com/54491/a-wire-of-15-resistance-is-gradually-stretched-to-double-its-original-length