Question

A wire of 180cm bent into a rectangle with length 60 cm. Find its breadth and area​

Answer 1

Step-by-step explanation:

Its breadth and area are 30 cm and 1800 sq.cm.

Step-by-step explanation:

Length of wire = 180 cm

Length of wire represents the perimeter of rectangle

Length of rectangle = 60 cm

Perimeter of rectangle = 2(l+b)=2(60+b)

So,180=2(60+b)180=2(60+b)

$\frac{180}{2}$

=60+b

90=60+b

30=b

So, Breadth is 30 cm

Area of rectangle = $Length \times Breadth = 60 \times 30 = 1800$

Hence its breadth and area are 30 cm and 1800 sq.cm.

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Answer 2

Step-by-step explanation:

Given :

length = 60cm

perimeter of wire = perimeter of rectangle (= 180cm)

perimeter of rectangle = (2×length) + (2×breadth)

(2×length) + (2×breadth) = 180cm

(2×60cm) + (2×breadth) = 180cm

120cm + (2×breadth) = 180cm

(2×breadth) = 180cm - 120cm

(2×breadth) = 60cm

breadth = 60/2 cm

breadth = 30cm

Area of rectangle = Length × breadth

= 60cm × 30cm

= 1800cm²