Question

a wire of 20 cm length placed in a magnetic field of 5 x10 power5 Tesla making an angle 60 degree with the
magnetic field if 10 mA current is flowing in it find the force acting on it?
​

Answer 1

Given:

A wire of 20 cm length placed in a magnetic field of 5 x10^5 Tesla making an angle 60 degree with the magnetic field , 10 mA current is flowing in it.

To find:

Force acting on the wire.

Calculation:

The general expression for force experienced by a current carrying conductor in in a magnetic field is given as follows :

$\boxed{ \bold{force = i \times L \times B \times \sin( \theta) }}$

So, putting the values in SI unit :

$= > \rm{force = i \times L \times B \times \sin( \theta) }$

$= > \rm{force = (10 \times {10}^{ - 3}) \times ( \dfrac{20}{100} ) \times (5 \times {10}^{5} )\times \sin( {60}^{ \circ} ) }$

$= > \rm{force = {10}^{ - 2} \times 0.2 \times 5 \times {10}^{5} \times \dfrac{ \sqrt{3} }{2} }$

$= > \rm{force = {10}^{ - 3} \times 5 \times {10}^{5} \times \sqrt{3} }$

$= > \rm{force =5 \sqrt{3} \times {10}^{ - 3 + 5} }$

$= > \rm{force =5 \sqrt{3} \times {10}^{2} }$

$= > \rm{force =500 \sqrt{3} \: newton }$

So, final answer is:

$\boxed{ \large{ \red{ \bf{force =500 \sqrt{3} \: newton }}}}$

Answer 2

$\bf \huge\red {</p><p>Answer :-</p><p>}$

$\green{ \implies \boxed{ \sf{ F = 35000 \: N \: {m}^{2}}} }</p><p>$

To Find :-

→ Force acting on wire .

Explanation :-

Given that

Length of wire (L) = 500m

current (i) = 35 Ampere

magnetic field (B) = 2 Tesla

Magnetic Force (F) = ?

We know that ,

$\orange{\begin{gathered}\implies \boxed{\sf{ F = iLB\sin\theta }\: } \\\end{gathered} }</p><p></p><p>$

Here Force is perpendicular hence angle be 90° .

$\begin{gathered}\implies \sf \pink{ F =35 \times 500 \times 2 \times \sin 90 \degree} \\ \\ \implies \boxed{ \sf{ F = 35000 \: N \:{m}^{2}}}\end{gathered} </p><p></p><p>$

Direction taken by right hand screw rule .

→ Thumb show direction of current and fingers show direction of magnetic field .