A wire of 24 om resistance is bent in the from of a equilateral triangle. The effective resistance in between any two corners is
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Answer: 16/3 ohms
Explanation :
As the wire is bent into an equilateral triangle, so the resistance of each of its side will be 1/3 of 24, that is 8 ohms.
Let R = 8 ohms
Therefore, if we see from any 2 corners of the triangle, there will be 2 wires in series which is then connected to 1 wire in parallel
So, the effective resistance will be (R+R) || R
Req = 2R || R
1/ Req = 1/2R + 1/ R
Req = 2R/3
= 2*8/3
= 16/3 ohms
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