Physics, asked by akash724876, 11 months ago

A wire of 3 ohm resistance and 15cm in length is stretched to 45cm lenght.Calculate 1.new cross sectional area 2.new resistance 3.resistivity. Assume that wire has uniform cross sectional area.

Answers

Answered by jacobpankavil
1

Answer:

Explanation:

resistance R=3ohm

length L=15cm=0.15m

R=resistivity L/A

3=rho 0.15/A

rho /A=3/0.15………1

new length L1=45cm=0.45m

The area is same then

New resistance R1 =rho L1/A

R1=3/0.15 x L1

R1=3x0.45/0.15

R1=9 Ohm

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