a wire of 440 M length is molded in the form of a circle and Square turn-by-turn find the ratio of the area of the circle to that of square
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circumference of circle=perimeter of square=440m
2πr=440
r=220/π
4s=440
s=110
πr²=π*(220/π)²
πr²=15406.2
s²=12100
πr²/s²=1.273
2πr=440
r=220/π
4s=440
s=110
πr²=π*(220/π)²
πr²=15406.2
s²=12100
πr²/s²=1.273
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let a be the side of square formed
since perimeter of square formed=440
4a=440
thus a=110
thus area of square=a^2=12100
Now, let r be the radius of circle formed.
since perimeter of circle formed=440
thus, 2πr=440
thus r=220/π
thus area of circle formed=πr^2=π(220/π)^2
=48400/π
thus Required ratio=(48400/π)/12100
=4/π
since perimeter of square formed=440
4a=440
thus a=110
thus area of square=a^2=12100
Now, let r be the radius of circle formed.
since perimeter of circle formed=440
thus, 2πr=440
thus r=220/π
thus area of circle formed=πr^2=π(220/π)^2
=48400/π
thus Required ratio=(48400/π)/12100
=4/π
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