Question

A wire of 48 ohm is bent to form an equilateral triangle resistance between any two vertices

Answer 1

Answer:

Explanation:

Resistance is directly proportional to the length of the wire

when the wire is bent in the form of an equilateral triangle the length becomes one third of the total length since the equilateral triangle has three equal sides

hence the resistance also becomes one third of the initial resistance

Hence resistance across any edge

= 18/3

=6 ohms But across any two vertices Two resistors series are in series Hence total resistance is 6 + 6 =12 ohms It is in parallel with 6 ohm resistor Hence finally it will be 12 × 6 / 12 + 6 = 4

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