Question

A wire of 5 Ω is stretched such that its length becomes thrice to its original. Calculate the new resistance.

Answer 1

Step-by-step explanation:

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$volume = \pir {2}^{2} l \\ l \: = 3l \: a = \frac{a}{3} \\ \\ we \: know \: \\ \\ r = \frac{ \:ρ×L \:}{a} \\ \\ hence \: = \frac{r}{r} = \frac{l}{l} \times \frac{a}{a} \\ \frac{3l}{l} \times \frac{a}{a3} = 9 \\ \\ hence \: \\ \\ r = 9r$

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