A wire of 58cm long 2mm diameter carries 750mA current when 22mV potential difference is applied at ends . If drift speed of e is found 1.7×10-5m/s then current density and number of free electrons per unit volume is
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Answer:
Given,
no of electrons=2*10^21
Average drift speed =0.25mm/s
Current=?
Current=Q/T
where Q=ne(no of electrons*charge on an electron)
Time=distance/speed
we get Q=2*10^21 * 1.6*10^-19
time=10mm/0.25mm
substituting the values,
I=2*10^21 * 1.6*10^-19 * 0.25/10*100
=8A
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