A wire of 9 resistance having 30 cm length is tripled on itself. What is its new resistance?
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R = p l/a Here p = constant
9 ohm = p 30/a
a = 30/9 m²
now length becomes 1/3 rd and area tripled
Therefore a = 30/9 * 3 = 10 m² and l = 1/3 * 30 = 10 m
Now R = p l/a
R = 10/10 = 1 ohm
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