A wire of diameter 3 mm and length 4 m extends by
2.5 mm when a force of 10 N is applied. Find the
Young's modulus of material of wire.
Answers
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Answer:
3.4 × 10⁷ N / m² .
Explanation:
Given :
Diameter of wire = 3 mm or 3 / 2 × 10⁻³ m
Length of wire = 4 m
Force = 10 N
Change in length = 2.5 mm or 2.5 × 10⁻³ m
Cross section area = π ( 3 / 2 × 10⁻³ )² m²
We know :
Y = F / A × L / Δ L
Y = 10 / π ( 3 / 2 × 10⁻³ )² × 4 / 2.5 × 10⁻³ N / m²
Y = 3.4 × 10⁷ N / m² .
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