Physics, asked by ashwin2602, 1 year ago

A wire of given material has a resistance of 8 ohm. what would be the resistance of the same wire when it streched double to its original length

Answers

Answered by balmiki008
0

the resistance will become 4 times =4*8=32 ohm is answer

Generalized if wire stretched n times its resistance becomes n*n times of previous

Answered by OoINTROVERToO
5

 \tt \: \blue{Resistnace \:  of \:  the \:  original \:  wire }   \\  \bf \: R  =  \frac{ ρL}{A},  \:  \:  \sf \: where  \: A= \frac{V}{L} \\  \\ \bf ⟹   R =  \frac{ρL²}{V} \\  \\ \cal \small { Now \:  its  \: length \:  is  \: stretched  \: such \:  that \:  new  \: length    }\\ \rm L′ = 2L \\  \\  \tt \: {Thus  \: resistance  \: of  \: the  \: wire}     \\   \rm \: R′ =  \frac{ρ(2L)²}{V} = 4R \\ \\ \red{  \small{ \bf Hence, \: resistance  \: becomes   \: 4   \: times  \: the  \: initial \:  resistance\ i.e\ 32\ Ω.}}

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