A wire of given material having length 1 and area of cross section A has a resistance of 4 ohm. What would be the resistance of another wire of the same material having length 1/2 (half) and area of cross section 2A?
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Answer:
It will remain same.
as R is directly proportional to length & inversely proportional to area.
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Material is same so rho is constant. In case 1 ,R proportional to length/area=1/A=4...(1). In case 2 R¹=L/A=1/2/2A=1/4A(2). Substitute (1) in (2).R¹=4/4=1 ohm.
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