Question

A wire of given material having length 1 and area of cross section
(A) has a resistance of 492. What would be the resistance of another
wire of the same material having length (C/2) and area of cross
section (2A)?

Answer 1

Answer:

Explanation:

y the formula of resistance:

R=(σ) L/A

here σ is resistivity, L is length of wire and A is area of cross section

Given. σ1=σ2. ______eq 1

for first material R1=σ1 L/A.

we can write.. σ1=R1A/L

σ1=4A/L.

for second material σ2 = R2.4A/L

from eq1. 4A/L=R24A/L

R2=0.

hope you understand

have a nice day..