Question

A wire of given material having length I and area of cross-section A
has a resistance of 40. What would be the resistance of another wire
of the same material having length 1/2 and area of cross-section 2A?
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Answer 1

Answer:

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Answer 2

R = rho X L / A = 40 ohm

R2 = rho X 0.5 L / 2A= 40 X 0.5 / 2
= 10 ohm