A wire of given material having length l and area of cross section A has resistance of 4Ω .What would be the resistance wire of another wire of same material l/2 and area of cross section 2A?
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Answer:
the resistance will be 1 ohm
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εηηο!❤
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As we know ,resistivity is
ρ=R x l/ A
So ,resistance is
R= ρ x l /A
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for first wire,
R1 = ρ x l/A =4Ω
For second wire,
R2 =ρ xl/2/2A = 1/4Ω
R2=1/4 R1
=>1/4 x4
=>1Ω
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the resistance of wire is 1Ω
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