Question

A wire of given material having length l and area of cross-section 'A' has a resistance of 27 ohms. What would be the resistance of the same material having length l/3 and area of cross-section 3A?​

Answer 1

Answer:

3Ω

Explanation:

In the 1st case,

Let the length be = l

Let the area of cross-section be =A

Resistance=27Ω

We know, R=ρl/A----------------------------(i)

In the 2nd case,

Length=l/3

Area=3A

Now,

R¹=ρl/3 ÷ 3A

R¹=ρl/9A----------------------------(ii)

From equation (i) and (ii) we get:

R¹=R*1/9

or R¹=27*1/9

or R¹=3Ω

I'M ALSO A BIG FAN OF IRON MAN> THANKS AND DON'T FORGT TO MARK AS THE BRAINLIEST:)