Question

A wire of given material having length l and area of cross-section A

has a resistance of 4 Ω. What would be the resistance of another wire

of the same material having length l/2 and area of cross-section 2A?​

Answer 1

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Answer 2

Explanation:

resistance = area of cross section/length

4ohm = A/l.....equn.1

Then resistance when length = l/2 and area = 2A

Multiply equn..1 by 2( for area to become 2A)

and divide by 1/2 ( for length to become l/2)4

I.e. 4ohm x 2 ÷ 1/2 = 2A/l ÷ 1/2

8 x 2 = 2A/l x 2

16ohm = 4A/l

Therefore the resistance of the material having

length l/2 and area of 2A is 16ohm .....

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