Chemistry, asked by varshalanjiwar40, 1 year ago

A wire of given material having length l and area of cross section A has a resistance of 10 ohm what would be the resistance of another wire of the same material having length 1/4and area of cross section 2.5A


varshalanjiwar40: please ans the questions

Answers

Answered by sarthakkhurana8
23
Here's Ur answer..
Hope it helps
Attachments:

sarthakkhurana8: Resistivity depends upon the material of conductor . Therefore it has not changed..
varshalanjiwar40: bhaiya R=p×1/4×2.5 a directly chAnge into 1/10
varshalanjiwar40: how
sarthakkhurana8: 4*2.5 equals 10.. And rho is common in both terms
sarthakkhurana8: Its just a relative relation that resistance of second wire is 1/10 Times that of first one
varshalanjiwar40: means l=1
sarthakkhurana8: No I don't mean that.. I mean that pl/A is common to both so they get cancelled..
sarthakkhurana8: U are just left with the ratio 1/10 whatever be the values of p,l and a
varshalanjiwar40: ok thanks bhaiya
sarthakkhurana8: welcome:)
Answered by soniatiwari214
2

Concept:

  • The resistance of a wire
  • The resistivity of a wire does not depend on the length and area of the cross section

Given:

  • Length of wire = L
  • Area of cross-section = A
  • Resistance of wire = 10 ohm
  • Length of new wire = L/4
  • Area of cross section = 2.5A

Find:

  • The new resistance of the wire

Solution:

Resistance = ρL/A

Resistance of original wire = 10ohm = ρL/A

Resistance of new wire = ρL/4A(2.5)

Resistance of new wire = ρL/10A = (1/10) ρL/A

But we know that ρL/A = 10 ohm

So, (1/10) ρL/A = 1/10 (10) = 1ohm

Resistance of new wire = 1 ohm

The new resistance of the wire is 1 ohm.

#SPJ2

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