A wire of given material having length l and area of cross section A has a resistance of 10 ohm what would be the resistance of another wire of the same material having length 1/4and area of cross section 2.5A
varshalanjiwar40:
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Here's Ur answer..
Hope it helps
Hope it helps
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Resistivity depends upon the material of conductor . Therefore it has not changed..
bhaiya R=p×1/4×2.5 a directly chAnge into 1/10
how
4*2.5 equals 10.. And rho is common in both terms
Its just a relative relation that resistance of second wire is 1/10 Times that of first one
means l=1
No I don't mean that.. I mean that pl/A is common to both so they get cancelled..
U are just left with the ratio 1/10 whatever be the values of p,l and a
ok thanks bhaiya
welcome:)
Answered by
2
Concept:
- The resistance of a wire
- The resistivity of a wire does not depend on the length and area of the cross section
Given:
- Length of wire = L
- Area of cross-section = A
- Resistance of wire = 10 ohm
- Length of new wire = L/4
- Area of cross section = 2.5A
Find:
- The new resistance of the wire
Solution:
Resistance = ρL/A
Resistance of original wire = 10ohm = ρL/A
Resistance of new wire = ρL/4A(2.5)
Resistance of new wire = ρL/10A = (1/10) ρL/A
But we know that ρL/A = 10 ohm
So, (1/10) ρL/A = 1/10 (10) = 1ohm
Resistance of new wire = 1 ohm
The new resistance of the wire is 1 ohm.
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