Question

A wire of given material having length land area of cross-section A
has a resistance of 4 22. What would be the resistance of another wire
of the same material having length 1/2 and area of cross-section 2A?​

Answer 1

Answer:

by the formula of resistance:

R=(σ) L/A

here σ is resistivity, L is length of wire and A is area of cross section

Given. σ1=σ2. ______eq 1

for first material R1=σ1 L/A.

we can write.. σ1=R1A/L

σ1=4A/L.

for second material σ2 = R2.4A/L

from eq1. 4A/L=R24A/L

R2=0.

hope you understand

have a nice day..