Question

A wire of given material L crossection area A resistance of 4 ohm.what would be resistance of another wire same material length
$\frac{l}{2}$
And area 2A​

Answer 1

Answer:

answer :

Wire of uniform cross-section has a resistance of R. Let the diameter be d, the length of the wire be l cross-sectional area be A.

Now the resistance of a wire can be expressed as:

R=p (1/A)

Where resistivity is ρ.

Now a second wire is twice as long and of half cross section.

Let final length be L1 , diameter be d and

cross section Area be A1

A1 = A/2

R1 = p (L1 / A1)

Putting the value of L1 =2L and A1=A/2

We have, resistance of the new second wire, R2 = p ( 4L/A )

=4×R1

=4×8=32Ω

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Answer 2

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