A wire of given materials length 'l' and area of cross section A has a resistance 10 ohm. What would be the resistance of another wire of the same materials having l/4 and area of cross section 2.5 A ?
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Answer:
hey mate your answer is
Explanation:
Resistance = p l/a [ p is constant]
For first wire length = l and area of croos section = a
Resistance = p l/a = 2.5 ohm [given]
For second wire length = l/2 and area of cross section = 2.5a
Resistance = p (l/2) / 2.5a
= p l/2.5a
= p l/a * 1/4 [p l/a = 2.5 ohm]
= 2.5*1/4 = 1.6 ohm
The resistance of second wire = 1.6ohm
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