Question

A wire of inform cross section and of resistance 10 ohm is cut into two equal parts the two pieces are then twisted around eachotherwhat will be the new resistance of wire​

Answer 1

Answer:

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be q

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R =

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = A

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql When it is cut then take each of the piece:-

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql When it is cut then take each of the piece:-Its resistance =

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql When it is cut then take each of the piece:-Its resistance = 2A

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql When it is cut then take each of the piece:-Its resistance = 2Aql

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql When it is cut then take each of the piece:-Its resistance = 2Aql

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql When it is cut then take each of the piece:-Its resistance = 2Aql =

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql When it is cut then take each of the piece:-Its resistance = 2Aql = 2

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql When it is cut then take each of the piece:-Its resistance = 2Aql = 2R

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql When it is cut then take each of the piece:-Its resistance = 2Aql = 2R

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql When it is cut then take each of the piece:-Its resistance = 2Aql = 2R

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql When it is cut then take each of the piece:-Its resistance = 2Aql = 2R When joined in parallel Net resistance =

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql When it is cut then take each of the piece:-Its resistance = 2Aql = 2R When joined in parallel Net resistance = 4

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql When it is cut then take each of the piece:-Its resistance = 2Aql = 2R When joined in parallel Net resistance = 4R

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be qTherefore R = Aql When it is cut then take each of the piece:-Its resistance = 2Aql = 2R When joined in parallel Net resistance = 4R

Explanation:

mark as brainlist answer