A wire of length 1 and resistance R has area of
cross-section A. What will be the length of the wire
of same material and same resistance R having area of cross-section A/3
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Answer:
I = 1.0 m
R = 23 ohm
p = 1.84 × 10-6 ohm – meter
We have
R = P. I/A
23 = 1.84 × 10-6 × 1/A
A = (1.84 × 10-6 )/23
= 0.08 × 10-6 m2
= 8 × 10-8 m2
Explanation:
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