Question

A wire of length 1 m 20 cm is cut into two equal pieces. One piece is bent to form square and the other one bent to form a rectangle of length a a​

Answer 1

Step-by-step explanation:

Length of wire = 1 m 20 cm = 100 cm + 20 cm = 120 cm

Wire is divided into two pieces

Length of 1 piece =\frac{120}{2} = 60 cm

2

120

=60cm

One piece is bent to form square

Perimeter of square = 4 \times Side4×Side

So, 4 \times Side = 60

Side = 15

Other one is bent to form rectangle of length 22cm.

Perimeter of rectangle = 2(l+b)=2(22+b)

So,2(22+b)= 60

22+b=30

b=8

Area of rectangle = Length \times Breadth = 22 \times 8 = 176 sq.cm.Length×Breadth=22×8=176sq.cm.

Area of square =Side^2 = 15^2 = 225 sq.cm.Side

2

=15

2

=225sq.cm.

Hence The area of rectangle is smaller than area of square