Question

A wire of length 1 m and 0.05cm is stretched by a force of 100N. If Y =2x10^11 N/m2 then find the elongation in the wire.​

Answer 1

Answer:

Explanation:

Young Modulus of Elasticity

Y=  

Al

FL

​  

 

F=  

L

YAl

​  

 

F=  

2

2×10  

11

×1×10  

−6

×10  

−3

×10  

−1

 

​  

 

F=100N

Work Done =  

2

1

​  

×100×1×10  

−3

×10  

−1

 

=0.005J

Work done = 5×10  

−3

joule