a wire of length 10 m has a resistance 100 ohm.if wire is stretched to increase its lenght three times what will be its new resistance?
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Answer:
we know that length is directly proportional to the resistance of the conductor
so, r1/r2 = l1/l2
from the given question, r1= 100ohms, l1= 10m.
according to the problem, length is increased 3times
so, l2 = 30m
then,
r1/r2=l1/l2
100/x=10/30
10x = 100×30
x = 100× 3
x ( resistance of the new wire ) = 300 ohms
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