a wire of length 10 m has resistance 100 w .wire is streched to increse three times , what will be its resistance ?
Answers
Answered by
0
Answer:
answer will be of resistance is = 1
Answered by
1
Answer:
hii
Explanation:
ur answer is here
Steps and Understanding:
1) On stretching the wire, it's length and Area of Cross section changes but Volume remains constant.
We know.
R = pl/A
R = pl * l /(A*l ) = pl^2/V
R α l^2
where
l. = length of wire
A = Area of cross section of wire.
V = Volume of wire.
2) After increasing the length of wire by 25%,then
Final length of wire, l(f) = 10 + 10 * (25/100)
= 10 + 2.5 = 12.5 m
We got that ,
R α l^2. -(1)
And
R(i) = 10ohm
R(f) = R
l(i) = 10m
l(f) = 12.5 ohm.
3)
Therefore, final resistance of wire is 15.625ohm.
Similar questions