Question

A wire of length 100 cm carries a steady current
i . The potentials at the ends of the wire is +4 V
and -20 V. The value of potential at x = 20 cm is​

Answer 1

The value of potential at x = 20 cm is​ - 4.8 V  and Voltage at 20 cm is +4 – 4.8 =  -0.8 V

Explanation:

In case of a constant Electric Filed E, the change in potential when moved through a distance  is the given by  -

$\Delta V= -E\l$     …………………(i)

Given that,

$\Delta V = -20 V - 4V = - 24V\\\\\l = 100 cm$

Now, From the equation (i)

$-24V = -E\l \\\\-E = \frac{-24V}{100}\\\\E = 0.24 \, Vm^{-1}$

Value of potential at x = 20 cm is

$\Delta V= -E\l\\\\\Delta V = -(0.24)\times 20\, cm\\\\\Delta V = - 4.8\, V$

Voltage at 20 cm is +4 – 4.8 = -0.8 V

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