A wire of length 120 m is bent to form the following shapes. Find the length of each
side of all the shapes.
a) A regular pentagon c) Regular hexagon
b) Equilateral triangle d) Square
Answers
Answered by
0
Answer:
its b or a
but i think its a
hope i answered correct
Answered by
1
Answer:
a)Perimeter of regular pentagon=Length of the wire
5x side = 120 m
side= 120/5
Side of regular pentagon = 24 m
b)Perimeter of Equilateral triangle=Length of the wire
3x side = 120 m
side= 120/3
Side of Equilateral triangle = 40 m
c)Perimeter of regular hexagon=Length of the wire
6x side = 120 m
side= 120/6
Side of regular hexagon = 20 m
d)Perimeter of square=Length of the wire
4x side = 120 m
side= 120/4
Side of square= 30m
Similar questions