Question

A wire of length 18 m had been tied with electric pole at an angle of elevation 30° with
the ground. Because it was covering a long distance, it was cut and tied at an angle of
elevation 60° with the ground. How much length of the wire was cut?
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Answer 1

Answer:

sin 30° = P/H

1/2 = P/18

9m= P

when , angle is 60°

sin 60°= 9/H

√3/2 = 9/H

18/√3 = H

multiply and divide by √3

so , H = 18√3/3

hence ,H =6√3 m

Step-by-step explanation: