A wire of length 18 m had been tied with electric pole at an angle of elevation 30° with
the ground. Because it was covering a long distance, it was cut and tied at an angle of
elevation 60° with the ground. How much length of the wire was cut?
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Answer:
sin 30° = P/H
1/2 = P/18
9m= P
when , angle is 60°
sin 60°= 9/H
√3/2 = 9/H
18/√3 = H
multiply and divide by √3
so , H = 18√3/3
hence ,H =6√3 m
Step-by-step explanation:
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