A wire of length 18m has been tied with electric pole at an angle of elevation 30deg with the ground.Because it was covering long distance,it was cut and tied at an angle of elevation 60deg with ground.How much length of the wire was cut?
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cos30=base\hypotenouse
√3\2=x\18
x=9√3
so base will be 9
then according to question
wire is cut and makes the angle of 60
cos 60 = base \hypotenuse
1\2=9√3/y
18√3=y
then the length cut out
9√3-18√3=9√3(1-2)
√3\2=x\18
x=9√3
so base will be 9
then according to question
wire is cut and makes the angle of 60
cos 60 = base \hypotenuse
1\2=9√3/y
18√3=y
then the length cut out
9√3-18√3=9√3(1-2)
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