Question

A wire of length 1m is placed perpendicular to a uniform magnetic field of magnitude 2T . What is the magnetic force on wire when the current flowing through it is 3 A ?
Please also write the formula while solving.​

Answer 1

F=IL×B where l is current,L is length and B is magnetic field.

= 3×1×2N

=6 N

Answer 2

Answer:

The magnetic force on the wire is 6 N.

Explanation:

Given that,

Length = 1 m

Magnetic field = 2 T

Current = 3 A

We need to calculate the magnetic force on the wire

Using formula of magnetic force

$F=il\times B$

$|F|=ilB\sin\theta$

Here, θ = 90°

Where, B = magnetic field

i = current

l = length

Put the value into the formula

$F=1\times2\times3$

$F=6\ N$

Hence, The magnetic force on the wire is 6 N.