Question

A wire of length 1m is stretched by a force of 10N. The area of cross-section of the wire is 2 × 10⁻⁶ m² & y is 2 × 10¹¹ N/m². Increase in length of the wire will be –
2.5 × 10⁻⁵ cm
2.5 × 10⁻⁵ mm
2.5 × 10⁻⁵ m
None​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

A wire of length 1m is stretched by a force of 10N. The area of cross-section of the wire is 2 × 10⁻⁶ m² & y is 2 × 10¹¹ N/m². An increase in the length of the wire will be  $2.5\times 10^{-5} m$

Explanation:

 

Young's modulus of a material (Y) is given by,

Y = $\frac{FL}{Al}$ ....(1)

where

F - Tension on the wire

L - Initial length of the wire

l -  Extended length

A - Area

Given,

L     =  1 m

A     =  $2\times10^{-6}$ $m^{2}$

F     =  10 N

Y     =  $2 \times 10^{11} \ N/m^{2}$

We have to find out l.

Using equation (1),

$l = \frac{FL}{AY}$

  = $\frac{10\times1}{2\times 10^{-6}\times 2\times 10^{11} }$

We get,

 l = $2.5\times 10^{-5} m$

   

Ans :

• Extended length of the wire  = $2.5\times 10^{-5} m$