A wire of length 2.5 m and area cross section 1×10^-6m2 has mass of 15kg hanging on it. How much energy stored in extended wire if young modulus of wire 2×10^11N/m2 ?
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Answer:
◆ Answer-
F = 150 N
◆ Explanation-
# Given-
L = 2.5 m
A = 1.5×10^-6 m^2
x = 2 mm = 2×10^-3 m
Y = 1.25×10^11 N/m^2
# Solution-
Tension produced in the wire is given by-
F = YAx / L
F = 1.25×10^11 × 1.5×10^-6 × 2×10^-3 / 2.5
F = 150 N
Therefore, tension produced in the wire is 150 N.
Hope that was useful..
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